#include <iostream>
using namespace std;
int k,a,sum;
int main()
{
    cin >> k;
    int n[k+5],d[k+5],e[k+5],j2;
    for(int i = 1;i<=k;i++) cin >> n[i] >> d[i] >> e[i];
    
    for(int i = 1;i<=k;i++){
        for(int j = 2;j<=n[i];j++){
            if(n[i] % j == 0){
                j2 = j;
                sum = d[i]*e[i];
                a = n[i] / j;
                if(((a-1) * (j-1) + 1) == sum){
                    cout << j << " " << a << endl;
                    break;
                }
            }
        }
        if(((a-1) * (j2-1) + 1) != sum){
            cout << "NO" << endl;
        }
    }
    
	return 0;
}