20分求调教
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20分求调教
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Czy8281016楼主2024/10/19 21:39
#include <bits/stdc++.h>
using namespace std;
int sx, sy; 
const int N = 3000;
int n, m, k, cnt = 0, fir[N], nxt[N << 1], to[N << 1], vis[N], cxy[N], nx = 0, p[N][N], cans = 0, ans[N], win[N], del[N];
char a[N][N];
void ade(int u, int v) {
    cnt++, nxt[cnt] = fir[u], fir[u] = cnt, to[cnt] = v;
    cnt++, nxt[cnt] = fir[v], fir[v] = cnt, to[cnt] = u;
}
int dfs(int r) {
    vis[r] = 1;
    for (int i = fir[r]; i; i = nxt[i])
        if (!vis[to[i]] && !del[to[i]]) {
            vis[to[i]] = 1;
            if (!cxy[to[i]] || dfs(cxy[to[i]])) {
                cxy[cxy[r]] = 0, cxy[to[i]] = r, cxy[r] = to[i];
                return 1;
            }
        }
    return 0;
}
void match() {
    for (int i = 1; i <= nx; i++)
        if (!cxy[i])
            memset(vis, 0, sizeof(vis)), dfs(i);
}
void getp() {//分成X,Y两部重标号
    int tmp = 0;
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
            if (a[i][j] == 'O')
                p[i][j] = ++tmp;
    nx = tmp;
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
            if (a[i][j] == 'X') p[i][j] = ++tmp;
            else if (a[i][j] == '.') p[i][j] = ++tmp, sx = i, sy = j;
}
int dx[5] = {0, 1, 0, -1};
int dy[5] = {1, 0, -1, 0};
void edge(int x, int y) {
    for (int i = 0; i < 4; i++) {
        int xx = x + dx[i], yy = y + dy[i];
        if (xx >= 1 && xx <= n && yy >= 1 && yy <= m && p[xx][yy] > nx) ade(p[x][y], p[xx][yy]);
    }
}
int main() {
    scanf("%d%d", &n, &m);
    for (int i = 1; i <= n; i++) scanf("%s", a[i] + 1);
    getp();
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= m; j++)
            if (a[i][j] == 'O')
                edge(i, j);
    match();
    scanf("%d", &k);
    
    for (int t = 1; t <= k * 2; t++) {
        del[p[sx][sy]] = 1;
        if (!cxy[p[sx][sy]]) continue;
        int tmp = cxy[p[sx][sy]];
        cxy[p[sx][sy]] = cxy[tmp] = 0, memset(vis, 0, sizeof(vis));
        if (!dfs(tmp)) win[t] = 1;
        scanf("%d%d", &sx, &sy);
    }
    for (int i = 2; i <= k * 2; i += 2)
        if (win[i] == 1 && win[i - 1] == 1)
            ans[++cans] = i / 2;
    printf("%d\n", cans);
    for (int i = 1; i <= cans; i++) printf("%d\n", ans[i]);
    return 0;
}
2024/10/19 21:39
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