#include<iostream>

using namespace std;

int main()
{
	int a, b, n;
	int m=0;
	cin >> a >> b >> n;
	if (a != b)
	{
		for (int i = 0; i < n; i++)
		{
			a = a * 10;
			m = a / b;//m为求出的余数
			a = (a-b*m) % 10;
	
		}
		cout << m << endl;
	}

	else
	{
		cout << "0" << endl;
	}
	return 0;
}