#include<bits/stdc++.h>
#define ll long long
using namespace std;
int n,a[200010],sum;
int main()
{
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>a[i];
		sum^=a[i];
	}
	for(int i=1;i<=n;i++)
		cout<<(sum^a[i])<<" ";
	return 0;
}
/*对于100%的数据,保证1<=n<=200000.

4
20 11 9 24

26 5 7 22
*/