RT
只是码量看着有点大当我没说,没任何思维难度和坑点。
映射的模板,这么几行就AC了
#include<bits/stdc++.h>
using namespace std;
map<string,int>s;
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n,op,cnt=0;
cin>>n;
while(n--)
{
string name;
int score;
cin>>op;
if(op==1)
{
cin>>name>>score;
if(s.find(name)==s.end()) cnt++;
s[name]=score;
cout<<"OK"<<'\n';
}
if(op==2)
{
cin>>name;
if(s.find(name)==s.end()) cout<<"Not found"<<'\n';
else cout<<s[name]<<'\n';
}
if(op==3)
{
cin>>name;
if(s.find(name)==s.end()) cout<<"Not found"<<'\n';
else
{
cnt--;
s.erase(name);
cout<<"Deleted successfully"<<'\n';
}
}
if(op==4)
{
cout<<cnt<<'\n';
}
}
return 0;
}