(1)$\begin{cases}\dfrac{1}{x+1}+\dfrac{2}{y-1}=15\\\\\dfrac{2}{x+1}+\dfrac{3}{y-1}=8\end{cases}$；

(2)$\begin{cases}\dfrac{xy}{3x-2y}=\dfrac{1}{8}\\\\\dfrac{xy}{2x+3y}=\dfrac{1}{6}\end{cases}$.

本人六年级蒟蒻不会解