同样是if反复判定 为什么两个思路一个倒着减回去只有60分 正着加上去的就满分了

60分版本如下

#include<bits/stdc++.h>
using namespace std;
int main()
{
	double  s, v;
	cin >> s >> v;
	double t1 = s / v;
	int t = ceil(t1);
	int h = t / 60;
	int m = t % 60;
	int H,M;
	if(h<=7)
	{
		H=7-h;
		if (m >= 50 && m<=59)
		{
			h = h + 1;
			m = m - 50;
			M = 60 - m;
			printf("0%d:0%d", H, M);
		}
		else if(m>=60)
		{
			h = h + 1;
			m = m - 50;
			M = 60 - m;
			printf("0%d:%d", H, M);
		}
		else
		{
			M = 50 - m;
			printf("0%d:%d", H, M);
		}
	} 
	else
	{
		H=24-(h-7);
		if (m >= 50 && m<=59)
		{
			h = h + 1;
			m = m - 50;
			M = 60 - m;
			printf("%d:0%d", H, M);
		}
		else if(m>=60)
		{
			h = h + 1;
			m = m - 50;
			M = 60 - m;
			printf("%d:%d", H, M);
		}
		else
		{
			M = 50 - m;
			printf("%d:%d", H, M);
		}	
	}
		
	return 0;
}

100分版本如下

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	double s, v;
	cin >> s >> v;
	int T, t1,t2;
	T = 24 * 60 + 8 * 60;
	t1 = ceil(s / v) + 10;
	t2 = T - t1;
	int h, m;
	h = t2 / 60;
	m = t2 % 60;
	if (h >= 24)
	{
		h = h - 24;
		if (m >= 10)
		{
			printf("0%d:%d", h, m);
		}
		
		else
		{
			printf("0%d:0%d", h, m);
		}
	}
	else if (h < 10)
	{
		if (m >= 10)
		{
			printf("0%d:%d", h, m);
		}

		else
		{
			printf("0%d:0%d", h, m);
		}
	}
	else
	{
		if (m >= 10)
		{
			printf("%d:%d", h, m);
		}

		else
		{
			printf("%d:0%d", h, m);
		}
	}
	return 0;
}

感谢帮助！！！