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_luanyi_楼主2024/9/8 21:20

第一篇有学术性错误。

具体地,

G(x)=G0(x)−ln⁡G0(x)−A(x)G0′(x)G0(x)=G0(x)(1−ln⁡G0(x)+A(x))G0′(x)G(x)=G_0(x)-\dfrac{\ln G_0(x)-A(x)}{\dfrac{G_0'(x)}{G_0(x)}}=\dfrac{G_0(x)(1-\ln G_0(x)+A(x))}{G_0'(x)}

应改为

G(x)=G0(x)−ln⁡G0(x)−A(x)1G0(x)=G0(x)(1−ln⁡G0(x)+A(x))G(x)=G_0(x)-\dfrac{\ln G_0(x)-A(x)}{\dfrac{1}{G_0(x)}}={G_0(x)(1-\ln G_0(x)+A(x))}

严重的学术性错误,极强的误导性,建议撤下。

2024/9/8 21:20
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