#include<bits/stdc++.h>
using namespace std;
long long n,a[200005],ans;
int main()
{
	scanf("%lld",&n);
	for(long long i=1;i<=n;i++)
	{
		scanf("%lld",&a[i]);
		if(a[i]%5==1) ans+=1;
		if(a[i]%5==2) ans+=2;
		if(a[i]%5>=3) ans+=3;
		ans+=a[i]/5*3;
	}
	printf("%lld",ans);
}

对了5个点（样例也过了）