改了好多次了，一直没过

另外求关于这种题目的ans赋值策略

#include<bits/stdc++.h>
#define int long long
using namespace std;
signed main(){
	int t;
	scanf("%lld",&t);
	while(t--){
		int l=1,r=1005,l1,l2,ans;
		while(l<=r){
			l1=l+(r-l)/3;
			l2=r-(r-l)/3;
			printf("? %lld %lld",l1,l2);
			cout<<endl;
			int s;
			scanf("%lld",&s);
			if(s==(l1+1)*(l2+1)){
				r=l1-1;
				ans=l1;
			}
			else if(s==l1*(l2+1)){
				l=l1+1;
				ans=l1+1;
				r=l2-1;
			}
			else{
				ans=l2+1;
				l=l2+1;
			}
		}
		printf("! %lld",ans);
		cout<<endl;
	}
	return 0;
}