$请求求解公式$

$e,d,n为常数，现有e$ $\times$ $d$ $-$ $n$ $=$ $2$ $-$ $p$ $-$ $q,n$ $=$ $p$ $\times$ $q,需求出p,q的值。$

$QWQ$ _ ω _

#include <iostream>
#include <cmath>
using namespace std;

bool isint(double n) {
    if (abs(n - int(n)) < 1e-9) {
        return true;
    }
    return false;
}

int main() {
    int k;
    cin >> k;
    for (int i = 1; i <= k; i++) {
        int n, e, d;
        cin >> n >> d >> e;
        //int p = _____;
        //int q = _____;
        if (isint(p) && isint(q)) {
            if (p > q) cout << q << ' ' << p;
            else cout << p << ' ' << q;
        }
        else cout << "NO";
        cout << endl;
    }
    return 0;
}