满江红

#include<bits/stdc++.h>
using namespace std;
int main(){
    long double M=-1,m=1e10000,sum=0,n;
    cin>>n;
    for(long long i=1;i<=n;i++){
        long double x;
        cin>>x;
        M=max(M,x);
        m=min(m,x);
        sum+=x;
    }
    printf("%.2llf %.2llf\n",(sum*1.0-M-m)/(n-2),sum*1.0/n-(sum*1.0-M-m)/(n-2));
    return 0;
}

急！