//p+q==n-(e*d)+2  n-(e*d)+2==p+(n/p)
#include <iostream>
#include <cmath>
using namespace std;
typedef long long shuju;
int main()
{
    shuju k=0;
    cin>>k;
    for(shuju i=0;i<k;i++)
    {
        long long n=0;
        shuju e=0;
        shuju d=0;
        cin>>n>>d>>e;
        bool OK=false;
        for(shuju p=1;p<=sqrt(n)+1;p++)
        {
            if(n%p!=0)
            {
                continue;
            }
            shuju q=n/p;
            if(p>q)
            {
                continue;
            }
            if(n-(e*d)+2==p+(n/p))
            {
                OK=true;
                cout<<p<<" "<<q<<endl;
                break;
            }
        }
        if(!OK)
        {
            cout<<"NO"<<endl;
        }
    }
    return 0;
}