说明/提示-样例解释1有误 被浪费的干草堆数量应为： 2(2−1)+2(2−2)+1(3−2)+1(4−2)+1(10−2)=2+0+1+2+8=13 2(2-1)+2(2-2)+1(3-2)+1(4-2)+1(10-2)={\color{red}2}+0+1+2+8=132(2−1)+2(2−2)+1(3−2)+1(4−2)+1(10−2)=2+0+1+2+8=13
