#include <iostream>
using namespace std;
int n,m,a[10005];
long long sum[10005];
int main()
{
	cin >> n;
	for (int i = 1;i <= n;i++)
	{
		cin >> a[i];
		sum[i] = a[i] + sum[i - 1];
	}
	cin >> m; 
	for (int i = 1;i <= m;i++)
	{
		int l,r;
		cin >> l >> r;
		cout << sum[r] - sum[l - 1] << endl;
	}
}