9 pts 求调
#include<bits/stdc++.h>
using namespace std;
//_______________________________________________________________________________________________________________________________________________________
const int N = 1000010;
struct tree{
int l, r;//区间
long long sum;//区间和
long long all_max;//区间最大子段和
long long left_max;//区间靠左最大子段和
long long right_max;//区间靠右最大子段和
int len(){return r - l + 1;}
};
int ls(int u){return u << 1;}
int rs(int u){return u << 1 | 1;}
int fa(int u){return u >> 1;}
long long w[N];
tree tr[N << 2];
void pushup(int u){
tree &root = tr[u], &lson = tr[ls(u)], &rson = tr[rs(u)];
root.sum = lson.sum + rson.sum;
root.left_max = max(lson.left_max, lson.sum + rson.left_max);
root.right_max = max(rson.right_max, rson.sum + lson.right_max);
root.all_max = max(max(max(root.left_max, root.right_max), max(lson.all_max, rson.all_max)), lson.right_max + rson.left_max);
}
void build(int l, int r, int u = 1){
if(l == r){
tr[u] = {l, r, w[l], w[l], w[l], w[l]};
}
else{
tr[u] = {l, r};
int mid = l + r >> 1;
build(l, mid, ls(u));
build(mid + 1, r, rs(u));
pushup(u);
}
}
void change(int k, long long w, int u = 1){//k处修改为w
if(tr[u].l == tr[u].r){
tr[u] = {tr[u].l, tr[u].r, w, w, w, w};
return;
}
int mid = tr[u].l + tr[u].r >> 1;
if(k <= mid) change(k, w, ls(u));
else change(k, w, rs(u));
pushup(u);
}
tree query(int l, int r, int u = 1){
if(l <= tr[u].l && tr[u].r <= r) return tr[u];
int mid = tr[u].l + tr[u].r >> 1;
if(r <= mid) return query(l, r, ls(u));//全在左儿子
else if(l > mid) return query(l, r, rs(u));//全在右儿子
else {//左右都访问
tree lson = query(l, r, ls(u)), rson = query(l, r, rs(u)), root;
//下面合并
root.left_max = max(lson.left_max, lson.sum + rson.left_max);
root.right_max = max(rson.right_max, rson.sum + lson.right_max);
root.all_max = max(max(root.left_max, root.right_max), max(lson.all_max, rson.all_max));
return root;
}
}
//_______________________________________________________________________________________________________________________________________________________
int n, m;
int main(){
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; i++) scanf("%lld", &w[i]);
build(1, n);
for(int i = 1; i <= m; i++){
int op, a, b;
scanf("%d%d%d", &op, &a, &b);
if(op == 1) printf("%lld\n", query(min(a, b), max(a, b)).all_max);
if(op == 2) change(a, b);
}
return 0;
}