和题解差不多的打表思路，看测试点没有什么问题

#include <iostream>
#include <string>
#include <cstdio>
using namespace std;

int main(void){
    string I, II, III, IV, V;
    string a = "XXX";
    string b = "..X";
    string c = "X.X";
    string d = "X..";
    char dot = '.';
    
    int n;
    cin >> n;
    getchar();
    string s;
    getline(cin, s);

    for(int i = 0;i < n;i++){
        int num = s[i] - '0';
        if(num == 0){
            I += a;
            II += c;
            III += c;
            IV += c;
            V += a;
        }
        else if(num == 1){
            I += b;
            II += b;
            III += b;
            IV += b;
            V += b;
        }
        else if(num == 2){
            I += a;
            II += b;
            III += a;
            IV += d;
            V += a;
        }
        else if(num == 3){
            I += a;
            II += b;
            III += a;
            IV += b;
            V += a;
        }
        else if(num == 4){
            I += c;
            II += c;
            III += a;
            IV += b;
            V += b;
        }
        else if(num == 5){
            I += a;
            II += d;
            III += a;
            IV += b;
            V += a;
        }
        else if(num == 6){
            I += a;
            II += d;
            III += a;
            IV += c;
            V += a;
        }
        else if(num == 7){
            I += a;
            II += b;
            III += b;
            IV += b;
            V += b;
        }
        else if(num == 8){
            I += a;
            II += c;
            III += a;
            IV += c;
            V += a;
        }
        else if(num == 9){
            I += a;
            II += c;
            III += a;
            IV += b;
            V += a;
        }

        if(i != n - 1)
        {
            I += dot;
            II += dot;
            III += dot;
            IV += dot;
            V += dot;
        }
    }
    cout << I << endl;
    cout << II << endl;
    cout << III << endl;
    cout << IV << endl;
    cout << V << endl;
    return 0;
}

输入 6 114514

输出为下

..X...X.X.X.XXX...X.X.X
..X...X.X.X.X.....X.X.X
..X...X.XXX.XXX...X.XXX
..X...X...X...X...X...X
..X...X...X.XXX...X...X