由 Xi+1=aXi+cX_{i+1}=aX_i+cXi+1=aXi+c 得 Xi=Xi+1−caX_i=\frac{X_{i+1}-c}{a}Xi=aXi+1−c ，所以有： [XiXi+100]×[0−a1a+1]=[Xi+1aXx+1+c00]=[Xi+1Xx+200]\left[ \begin{array}{cc}X_i&X_{i+1}\\0&0\end{array}\right]\times\left[ \begin{array}{cc}0&-a\\1&a+1\end{array}\right]=\left[ \begin{array}{cc}X_{i+1}&aX_{x+1}+c\\0&0\end{array}\right]=\left[ \begin{array}{cc}X_{i+1}&X_{x+2}\\0&0\end{array}\right][Xi0Xi+10]×[01−aa+1]=[Xi+10aXx+1+c0]=[Xi+10Xx+20]
如图：
但写出来过不了样例，交上去只有30分
代码
