0分求调,悬赏一个关注
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0分求调,悬赏一个关注
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n_bluetea楼主2024/6/14 21:30
#include<bits/stdc++.h>
using namespace std;

const int maxn = 1e5 + 100;
int d[maxn], c[maxn], nexts[maxn];

struct edge {
    int to, next;
} e[maxn];

int cnt = 1;
int head[maxn];

void add(int u, int v) {
    e[cnt].to   = v;
    e[cnt].next = head[u];
    head[u]     = cnt++;
}

int deep[maxn];
int ance[maxn][21]; 
int tale[maxn][21];

void dfs(int now, int fa) {
    ance[now][0] = fa;
    tale[now][0] = c[fa];
    deep[now]    = deep[fa] + 1;
    
    //构建now的2^x级祖先
    for (int i = 1; (1<<i)<=deep[now]; i++) {
        ance[now][i] = ance[ance[now][i - 1]][i - 1];
        tale[now][i] = tale[ance[now][i - 1]][i - 1] + tale[now][i - 1];
       
    }

    for (int i = head[now]; i; i = e[i].next) {
        int tx = e[i].to;
        if (tx == fa) continue;
        dfs(tx, now);
    }
}

int main() {
    int n, m;
    cin >> n >> m;

    for (int i = 1; i <= n; i++) {
        cin >> d[i] >> c[i];
    }

    //找出第i个圆盘后面第一题比它大的圆盘
    stack<int> s;
    s.push(1);
    d[n+1] = INT_MAX;
    c[n+1] = INT_MAX;
    for (int i = 2; i <= n+1; i++) {
        while (!s.empty() && d[s.top()] < d[i]) {
            nexts[s.top()] = i;
            s.pop();
        }
        s.push(i);
    }

    //将连接关系构建成图
    for (int i = 1; i <= n; i++) {
        add(nexts[i], i);
    }

    
    dfs(n + 1, 0);
    for (int i = 1; i <= m; i++) {
        int r, v;
        cin >> r >> v;

        if (c[r] >= v) {
            cout << r << "\n";
            continue;
        }

        v-=c[r];
        int x = r;
        int ans = 0;
        for (int j = 20; j >= 0; j--) {
            if (deep[x] >= (1 << j) && tale[x][j] <= v) {
                v -= tale[x][j];
                x  = ance[x][j];
            }
            if (v == 0) {
                ans = x;
            }
        }

        if (ans == 0)
            ans = ance[r][0];
        if (ans == n + 1)
            ans = 0;
         
        if (ans==0)   ans=ance[x][0];
	    if (ans==n+1) cout<<0<<endl;else cout<<ans<<endl;
    }

    return 0;
}

2024/6/14 21:30
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