佬若找到代码的bug，可以在该帖子发布，作者定期查看,dctc800d的已解决

#include<bits/stdc++.h>
#include<windows.h>
using namespace std;
int a,n,v[1001],x[1001],y[1001],l[1001],p[1001],wrong;
string z[1001]; 
int main(){
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	cin>>a;
	cin.ignore();
	for(int i=1;i<=a;i++)getline(cin,z[i]);
	for(int i=1;i<=a;i++){
		int shu=0,c=0,d=1;
		string b;
		for(int j=0;j<=z[i].size();j++){
			if(z[i].size()==0||!v[i]&&b==""&&z[i].size()==j){
				cout<<"错误"<<++wrong<<"：第"<<i<<"行："<<"不可以是空串或全是空格\n";
			}
			if(z[i][j]==' '||j==z[i].size()){
				if(c==0&&b.size()==0)continue;
				if(b==""&&!v[i])continue;
				if(!v[i]){
					if(b=="new")v[i]=1;
					else if(b=="dec")v[i]=2;
					else if(b=="assign")v[i]=3;
					else if(b=="iftry")v[i]=4;
					else if(b=="ifeq")v[i]=5;
					else if(b=="ifneq")v[i]=6;
					else {
						cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：没有"<<b<<"这个语法\n";
						break;
					}
				}if(v[i]==4&&shu==1||v[i]==5&&shu==2||v[i]==6&&shu==2){
					if(b!="goto"){
						cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列："<<b<<"应为goto\n";
						break;
					}shu++;
				}if(v[i]){
					if(c>0)shu++;
					if(v[i]==1){
						if(c>1000){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
							break;
						}if(shu!=1&&j==z[i].size()){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：new 语法的格式应为 new x\n";
							break;
						}x[i]=c;
					}else if(v[i]==2){
						if(c>1000){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
							break;
						}if(shu!=1&&j==z[i].size()){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：dec 语法的格式应为 dec x\n";
							break;
						}x[i]=c;
					}else if(v[i]==3){
						if(c>1000){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
							break;
						}if(shu!=2&&j==z[i].size()){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：assign 语法的格式应为 assign x y\n";
							break;
						}if(shu==1)x[i]=c;
						if(shu==2)y[i]=c;
					}else if(v[i]==4){
						if(shu!=3&&j==z[i].size()){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：iftry 语法的格式应为 iftry x y goto l\n";
							break;
						}
						if(shu==3&&c>=i){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：l应小于当前条数"<<i<<"\n";
							break;
						}else{
							if(c>1000){
								cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
								break;
							}
						}if(shu==1)x[i]=c;
						if(shu==3)l[i]=c;
					}else if(v[i]==5){
						if(shu!=4&&j==z[i].size()){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：ifeq 语法的格式应为 ifeq x y goto l\n";
							break;
						}
						if(shu==4&&c>=i){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：l应小于当前条数"<<i<<"\n";
							break;
						}else{
							if(c>1000){
								cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
								break;
							}
						}if(shu==1)x[i]=c;
						if(shu==2)y[i]=c;
						if(shu==4)l[i]=c;
					}else if(v[i]==6){
						if(shu!=4&&j==z[i].size()){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：ifneq 语法的格式应为 ifneq x y goto l\n";
							break;
						}
						if(shu==4&&c>=i){
							cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：l应小于当前条数"<<i<<"\n";
							break;
						}else{
							if(c>1000){
								cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
								break;
							}
						}if(shu==1)x[i]=c;
						if(shu==2)y[i]=c;
						if(shu==4)l[i]=c;
					}  
				}
				c=0;
				b="";
				d=j+2;
			}else if(v[i]==0||v[i]==4&&shu==1||v[i]==5&&shu==2||v[i]==6&&shu==2)b+=z[i][j];
			else {
				if(c==0&&z[i][j]=='0'){
					cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<j<<"列：数字开头不能为0/数字不能为0\n";
					break;
				}if(z[i][j]>'9'||z[i][j]<'0'){
					cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<j<<"列：数字中不能出现不是数字的字符\n";
					break;
				}c=c*10+z[i][j]-48; 
			}
		}
	}
	if(wrong)return 0;
	printf("编译成功\n");
	printf("请输入n\n");
	while(1){
		cin>>n;
		if(n<=100&&n>=5)break;
		printf("5<=n<=100，请重输\n");
	}
	
	int mm=0; 
	p[1]=n;
	for(int i=1;i<=a;){
		mm++;
		
		if(mm>100000){
			printf("运行次数超过100000次，或进入死循环");
			return 0;
		}
		if(v[i]==1)n++,p[x[i]]++,i++;
		else if(v[i]==2)p[x[i]]--,i++;
		else if(v[i]==3)p[x[i]]=p[y[i]],i++;
		else if(v[i]==4){
			if(p[x[i]]>=0)i=l[i];
			else i++;
			continue;	
		}else if(v[i]==5){
			if(p[x[i]]==p[y[i]])i=l[i];
			else i++;
			continue;	
		}else if(v[i]==6){
			if(p[x[i]]!=p[y[i]])i=l[i];
			else i++;
			continue;	
		}
	}printf("输出的结果是：%d\n",n);
	if(a>1000){
		printf("条数大于1000条，请寻找更优解\n");
		return 0;
	}
	return 0;
}