线段树维护区间最大和最小在2e5为什么会超时呢
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线段树维护区间最大和最小在2e5为什么会超时呢
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senak楼主2024/5/8 14:02

上周abc的D题,排序后滑动窗口用线段树维护最大位置和最小位置为什么会超时呢?请求大佬指点

#include<iostream>
#include<vector>
#include<algorithm>
#define lc p<<1
#define rc p<<1|1
using namespace std;
const int N = 2E5 + 7;
struct Node {
	int a, id;
}a[N];
bool cmp(Node a, Node b) {
	return a.a < b.a;
}
struct Node2 {
	int mx, mn;
}t[N << 2];
void pushup(int p) {
	t[p].mx = max(t[lc].mx, t[rc].mx);
	t[p].mn = min(t[lc].mn, t[rc].mn);
}
void pushdown(int p) {

}
pair<int, int> query(int p, int L, int R,int l,int r) {
	if (L > r || R < l) return { 0 ,1e9};
	if (L <= l && r <= R) {
		return { t[p].mx,t[p].mn };
	}
	int m = l + r >> 1;
	pushdown(p);
	pair<int, int>res = { 0,1e9 };
	res.first = max(query(lc, L, R,l,m).first, query(rc, L, R,m+1,r).first);
	res.second = min(query(lc, L, R,l,m).second, query(rc, L, R,m+1,r).second);
	return res;
}
void build(int p, int l, int r) {
	t[p] = { a[l].id,a[r].id };
	if (l == r)return;
	int m = l + r >> 1;
	build(lc, l, m);
	build(rc, m + 1, r);
	pushup(p);
}
void solve() {
	int n, k; cin >> n >> k;
	for (int i = 1; i <= n; i++) {
		cin >> a[i].a; a[i].id = i;
	}
	sort(a + 1, a + 1 + n, cmp);
	build(1, 1, n);
	int kk = 1, ans = 1e9;
	int Last = 1;
	for (int i = 1; i <= n; i++, kk++) {
		if (kk == k) {
			pair<int, int>pii = query(1, Last, i,1,n);
			int mx = pii.first, mn = pii.second;
			ans = min(ans, mx - mn);
			kk--;
			Last++;
		}
	}cout << ans << endl;
}
int main() {
	solve();
	return 0;
}
2024/5/8 14:02
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