假设 a=3,b=1,c=0,d=1+1a=3,b=1,c=0,d=1+1a=3,b=1,c=0,d=1+1。可得 a−d−b=2ca-d-b=2ca−d−b=2c。
所以：
a−d=b+2ca-d=b+2ca−d=b+2c
(a−d)2=(a−d)(b+2c)(a-d)^2=(a-d)(b+2c)(a−d)2=(a−d)(b+2c)
(a−d)2−(2c+b)2=(a−d)b+2(a−d)c−(2c+b)2(a-d)^2-(2c+b)^2=(a-d)b+2(a-d)c-(2c+b)^2(a−d)2−(2c+b)2=(a−d)b+2(a−d)c−(2c+b)2
(a−2c−b−d)(a−d+2c+b)=(a−d−2c−b)(b+2c)(a-2c-b-d)(a-d+2c+b)=(a-d-2c-b)(b+2c)(a−2c−b−d)(a−d+2c+b)=(a−d−2c−b)(b+2c)
a−d+2c+b=b+2ca-d+2c+b=b+2ca−d+2c+b=b+2c
a+2c+b−b−2c=da+2c+b-b-2c=da+2c+b−b−2c=d
a=da=da=d
d=ad=ad=a
所以 1+1=31+1=31+1=3。
这个证明错在哪？
