给定 nnn,如何求出
F(z)=(1+z)((n−1)2n+1zn+1−n2nzn(z+1)2+2z(z+1)2n)(1+z)2(modz2n+1)F(z)=\dfrac{(1+z)((n-1)2^{n+1}z^{n+1}-n2^nz^n(z+1)^2+2z(z+1)^{2n})}{(1+z)^2}\pmod{z^{2n+1}}F(z)=(1+z)2(1+z)((n−1)2n+1zn+1−n2nzn(z+1)2+2z(z+1)2n)(modz2n+1)
的每一项系数。