这注释部分和底下的有什么不同吗,思路一样的fhq我是真不理解为啥注释部分不能ac底下就可以
#include<bits/stdc++.h>
int root=0,tot=0;
struct FHQ_treap{
struct fhq_treap{
int l,r,val,siz,dat;
}tree[500005];
inline void update(int x){
tree[x].siz=tree[tree[x].l].siz+tree[tree[x].r].siz+1;
return ;
}
inline int newnode(int x){
tree[++tot].val=x;
tree[tot].siz=1;
tree[tot].dat=rand();
return tot;
}
inline void split(int k,int key,int &x,int &y){
if(k==0){
x=y=0;
return ;
}
if(tree[k].val<=key){
x=k;
split(tree[x].r,key,tree[x].r,y);
}
else{
y=k;
split(tree[y].l,key,x,tree[y].l);
}
update(k);
return ;
}
inline int merge(int x,int y){
if(x==0){
return y;
}
if(y==0){
return x;
}
if(tree[x].dat>tree[y].dat){
tree[x].r=merge(tree[x].r,y);
update(x);
return x;
}
else{
tree[y].l=merge(x,tree[y].l);
update(y);
return y;
}
}
//bug on last
/*void insert(int key){
int x,y;
split(root,key-1,x,y);
int id=newnode(key);
root=merge(merge(x,id),y);
return ;
}
void remove(int key){
int x,y,z;
split(root,key-1,x,y);
split(y,key,y,z);
if(y){
y=merge(tree[y].l,tree[y].r);
}
root=merge(merge(x,z),y);
return ;
}
int rnk(int key){
int x,y,ans;
split(root,key-1,x,y);
ans=tree[x].siz+1;
root=merge(x,y);
return ans;
}
int kth(int rnk){
int p=root;
while(1){
if(tree[tree[p].l].siz+1==rnk){
break;
}
else if(tree[tree[p].l].siz+1>rnk){
p=tree[p].l;
}
else{
rnk-=tree[tree[p].l].siz+1;
p=tree[p].l;
}
}
return tree[p].val;
}
int pre(int key){
int x,y,p;
split(root,key-1,x,y);
p=x;
while(tree[p].r!=0){
p=tree[p].r;
}
root=merge(x,y);
return tree[p].val;
}
int next(int key){
int x,y,p;
split(root,key-1,x,y);
p=y;
while(tree[p].l!=0){
p=tree[p].l;
}
root=merge(x,y);
return tree[p].val;
}*/
void insert(int key) { //插入键值为key的数
int x, y;
split(root, key - 1, x, y); //把小于等于key-1的分给x 大于等于key的分给y
int id = newnode(key);
root = merge(merge(x, id), y); //把新节点插入到x,y之间
}
void remove(int key) { //删除一个键值为key的数
int x, y, z;
split(root, key - 1, x, y); //把小于等于key-1的分给x
split(y, key, y, z); //把大于key的分给z 那y中就全是等于key的了
if (y) y = merge(tree[y].l, tree[y].r); //因为只需要删除一个数 所以把根节点删掉左右俩儿子合并
root = merge(merge(x, y), z); //然后重新合起来 如果要把权值为key的全删掉就把xz合起来
}
int rnk(int key) { //查询key的排名
int x, y, ans;
split(root, key - 1, x, y); //把小于key的数都分给x 那么siz[x]就是小于key的数的数量
ans = tree[x].siz + 1;
root = merge(x, y); //掰完记得合起来
return ans;
}
int kth(int rnk) { //查询排名为rnk的数
int p = root;
while (p) {
if (tree[tree[p].l].siz + 1 == rnk) break; //正正好好查到
else if (tree[tree[p].l].siz + 1 > rnk) p = tree[p].l; //查过头了
else {
rnk -= tree[tree[p].l].siz + 1;
p = tree[p].r; //还不够
}
}
return tree[p].val;
}
int pre(int key) { //查询key的前驱
int x, y, p;
split(root, key - 1, x, y); //把比key小的都分给x
p = x;
while (tree[p].r != 0) p = tree[p].r; //一直往大的方向走
root = merge(x, y);
return tree[p].val;
}
int next(int key) { //查询key的后缀
int x, y, p;
split(root, key, x, y); //把比key大的都分给y
p = y;
while (tree[p].l != 0) p = tree[p].l;
root = merge(x, y);
return tree[p].val;
}
}treap;
int n;
int main(){
srand(time(0));
scanf("%d",&n);
for(int i=1;i<=n;i++){
int opt,x;
scanf("%d%d",&opt,&x);
if(opt==1){
treap.insert(x);
}
else if(opt==2){
treap.remove(x);
}
else if(opt==3){
printf("%d\n",treap.rnk(x));
}
else if(opt==4){
printf("%d\n",treap.kth(x));
}
else if(opt==5){
printf("%d\n",treap.pre(x));
}
else{
printf("%d\n",treap.next(x));
}
}
}