站外题30分求救(大量玄关)
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  • 发布时间2024/4/1 12:04
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站外题30分求救(大量玄关)
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2345A楼主2024/4/1 12:04

题目描述 给出 (行)和 (列)和一个 行 列的表格,找出其中的“snuke”。先输出列(用A~Z表示),在输出行(用数字表示)中间不带空格

输入格式 第一行,两个整数,表示 (行)和 (列)

接下来 行,每行 个字符串

输出格式
snuke 所在的位置,行和列之间不加空格

样例输入 #1

15 10
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snuke snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake
snake snake snake snake snake snake snake snake snake snake

样例输出 #1

H6

样例输入 #2

1 1
snuke

样例输出 #2

A1

30分代码;


#include<bits/stdc++.h>
using namespace std;
int main() 
{
    int a,b;
    cin>>a>>b;
    string c[a+10];
    for(int i=0;i<a;i++)
	{
        for(int j=0;j<b;j++) 
        cin>>c[i][j];
    }

    for(int i=0;i<a;i++)
	{
        for(int j=0;j<b;j++) 
		{
            if(c[i][j]='u') 
			{
                cout<<char(j+65)<<i+1;
                return 0;
            }
        }
    }

    return 0;
}
2024/4/1 12:04
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