x1′′+kx1(1m1+1m2)=km0gt22m1m2x_1''+kx_1(\frac{1}{m_1}+\frac{1}{m_2})=\frac{km_0gt^2}{2m_1m_2}x1′′+kx1(m11+m21)=2m1m2km0gt2
物理题。