输出n不能用printf! ! ! !
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输出n不能用printf! ! ! !
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zhangzirui66楼主2024/1/24 12:25
#include<bits/stdc++.h>
using namespace std;
int ans[10001], n, j = 1;
char a, b = '0';
int main(){
	while(cin >> a){
		n ++;
		if(a == b) ans[j] ++;
		else{
			b = a;
			ans[++ j] ++;
		}
	}
	printf("%d ", sqrt(n));
	for(int i = 1; i <= j; i ++) printf("%d ", ans[i]);
	return 0;
}

这样sqrt(n)是错的

#include<bits/stdc++.h>
using namespace std;
int ans[10001], n, j = 1;
char a, b = '0';
int main(){
	while(cin >> a){
		n ++;
		if(a == b) ans[j] ++;
		else{
			b = a;
			ans[++ j] ++;
		}
	}
	cout << sqrt(n) << " ";
	for(int i = 1; i <= j; i ++) printf("%d ", ans[i]);
	return 0;
}

改成cout就对了

2024/1/24 12:25
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