第四个点超时,用dfs
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  • 楼主ansan
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  • 发布时间2024/1/22 15:41
  • 上次更新2024/1/22 18:58:15
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第四个点超时,用dfs
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ansan楼主2024/1/22 15:41
using namespace std;
const int N = 50;
bool vis[N][N];
int dx[4] = {1, -1, 0, 0};
long long dy[4] = {0, 0, 1, -1};
long long cha[50][50];
long long a[50][50];
long long n;
void dfs(int x, int y){
    for(int i = 0; i < 4; i++){
        int xx = x + dx[i], yy = y + dy[i];
            if(xx >= 0 && xx <= n+1 && yy >= 0 && yy <= n+1 && !vis[xx][yy]){
                vis[xx][yy] = 1;
                cha[xx][yy] = -1;
                dfs(xx,yy);
                vis[xx][yy] = 0;
            }
    }
    return;
}
int main(){
    cin >> n;
    for(int i = 1; i <= n; i++){
    	for(int j = 1; j <= n; j++){
    		cin >> a[i][j];
    		if(a[i][j] == 1)
    		vis[i][j] = 1;
		} 
	}
	vis[0][0] = 1;
    dfs(0,0);
	for(int i = 1; i <= n; i++){
		for(int j = 1; j <= n; j++){
			if(a[i][j] == 0 && cha[i][j] != -1)
			a[i][j] = 2;
			cout << a[i][j] << " ";
		}
		cout << "\n";
	}
    return 0;
}
2024/1/22 15:41
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