具体见 https://www.luogu.com.cn/blog/Bingxiu/solution-p3769
叉掉只需要 222 个 (0,0,0,0)(0,0,0,0)(0,0,0,0),100001000010000 个 (0,0,k,−k)(k∈Z+)(0,0,k,-k)(k \in \mathbb{Z^+})(0,0,k,−k)(k∈Z+),111 个 (0,1,0,0)(0,1,0,0)(0,1,0,0) 即可,因为按照瞎搞最后一个点会和后 750075007500 个点计算得到答案为 ∣{(0,0,0,0),(0,0,0,0)}∣=2|\{(0,0,0,0),(0,0,0,0)\}|=2∣{(0,0,0,0),(0,0,0,0)}∣=2,但实际上最后一个点也可以加入答案得到 LIS 为 333