没开O2记录 和 开O2记录

代码都一样

#include <bits/stdc++.h>
using namespace std;
const int maxn = 3e3;
int n,m,a[maxn],s[maxn],ans = 100 * maxn + 50;
int main(){
	scanf("%d%d",&n,&m);
	for (int i = 1; i <= n; i++) scanf("%d",&a[i]);
	s[0] = 0;
	for (int i = 1; i <= n; i++) s[i] = s[i - 1] + a[i];
	for (int i = m; i <= n; i++) ans = min(ans,s[i] - s[i - m]);
	printf("%d",ans);
	return 0;
}