#include <bits/stdc++.h>

using namespace std;

int main()

{

	int n; cin>>n;
    
    doublea[n],sum=0,u=0,l=1000000,e,q;;
    
    double ou;
    
    for(int i=0;i<n;i++)
    
    {
    
        cin>>a[i];
        
        sum+=a[i];
        
		if(a[i]>=u)
        
        {
        
            u=a[i];
            
        }
        
		if(a[i]<=l)
        
        {
        
            l=a[i];
            
        }
        
    }
    
    sum=sum-u-l;
    
    sum=sum/(n-2);
    
    printf("%.2lf",sum);
    
    cout<<" ";
    
    e=sum-l;
    
    q=u-sum;
    
    if(e>q)
    
    printf("%.2lf",e-1);
    
    else
    
    printf("%.2lf",q-1);
    
	return 0;
    
}

//只通5个