无序输入四个点的坐标，判断矩形，大佬请看下面我的做法哪里错了```cpp #include #include using namespace std;

int main() { int s[10001][8]={0},temp=0,o[10001]={0}; int k[6]={0},d1,d2,d3,d4; int t; double a,b; cin>>t; for(int i=0;i<t;i++) {

    cin>>s[i][0]>>s[i][1]>>s[i][2]>>s[i][3]>>s[i][4]>>s[i][5]>>s[i][6]>>s[i][7];
    a=1.0*(s[i][0]+s[i][2]+s[i][4]+s[i][6])/4;
    b=1.0*(s[i][1]+s[i][3]+s[i][5]+s[i][7])/4;
    d1=(a-s[i][0])*(a-s[i][0])+(b-s[i][1])*(b-s[i][1]);
    d2=(a-s[i][2])*(a-s[i][2])+(b-s[i][3])*(b-s[i][3]);
    d3=(a-s[i][4])*(a-s[i][4])+(b-s[i][5])*(b-s[i][5]);
    d4=(a-s[i][6])*(a-s[i][6])+(b-s[i][7])*(b-s[i][7]);
    k[0]=(s[i][0]-s[i][2])*(s[i][0]-s[i][2])+(s[i][1]-s[i][3])*(s[i][1]-s[i][3]);
    k[1]=(s[i][2]-s[i][4])*(s[i][2]-s[i][4])+(s[i][3]-s[i][5])*(s[i][3]-s[i][5]);
    k[2]=(s[i][4]-s[i][6])*(s[i][4]-s[i][6])+(s[i][5]-s[i][7])*(s[i][5]-s[i][7]);
    k[3]=(s[i][6]-s[i][0])*(s[i][6]-s[i][0])+(s[i][7]-s[i][1])*(s[i][7]-s[i][1]);

    k[4]=(s[i][0]-s[i][4])*(s[i][0]-s[i][4])+(s[i][1]-s[i][5])*(s[i][1]-s[i][5]);
    k[5]=(s[i][2]-s[i][6])*(s[i][2]-s[i][6])+(s[i][3]-s[i][7])*(s[i][3]-s[i][7]);

   
    for(int j=0;j<5;j++)
    {
        for(int h=0;h<5-j;h++)
        {
            if(k[h]>k[h+1])
            {
                temp=k[h],k[h]=k[h+1],k[h+1]=temp;
            }
        }
    }

     if(d1==d2&&d2==d3&&d3==d4)
     {
       if(k[0]==k[1]&&k[2]==k[1]&&k[3]==k[2]) o[i]=0;
       else o[i]=1;
     }
     else o[i]=2;
    memset(k,0,sizeof(k)); 
}  
for(int i=0;i<t;i++)
{
    if(o[i]==0) cout<<"square";
    else if(o[i]==1) cout<<"rectangle";
    else cout<<"no";
    if(i!=t-1) cout<<endl; 
}
return 0;

}