求助,#2WA了
查看原帖
求助,#2WA了
1097566
Foxinwrongpath楼主2023/11/15 20:34
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
	double a,b,c,x1,x2;
	cin>>a>>b>>c;
	double d=b*b-4*a*c;
	if(d>0){
		x1=(-b+sqrt(d))/(2*a);
		x2=(-b-sqrt(d))/(2*a);
		if(x1>x2) swap(x1,x2);
		printf("x1=%.5f;x2=%.5f",x1,x2);
	}else if(d==0){
		x1=(-b)/2*a;
		printf("x1=x2=%.5f",x1);
	}else printf("No answer!");
	return 0;
}

如代码

2023/11/15 20:34
加载中...