#include<bits/stdc++.h>
using namespace std;
int main(){
	long long n,m,numa,numb;
	cin >> n >> m;
	for(int i = 1;i <= n;i++){
		for(int j = 1;j <= m;j++){
			if (i == j)numa += (n-i+1)*(m-i+1);	
			else numb += (n-i+1)*(m-j+1);
		}
	} 
	cout << numa << " " << numb;
	return 0;
} 

运用原理：