#include <bits/stdc++.h>
typedef long long LL;
const int N = 1e5 + 5;
int n;
LL a[N], qk[N], qb[N];
struct Edge { int to, nxt; } edge[N << 1];
int head[N];
void add_edge(int u, int v) { static int k = 1; edge[k] = (Edge){v, head[u]}, head[u] = k++; }
int bd[N], cnt[N];
void dfs(int u, int fa) {
for(int i = head[u]; i; i = edge[i].nxt) if(edge[i].to != fa) {
int v = edge[i].to;
dfs(v, u);
bd[u] = std::min(bd[u], bd[v] - 1);
}
}
inline LL div_ceil(LL x, LL y) { if(y < 0) x = -x, y = -y; return x < 0 ? x / y : (x + y - 1) / y; }
inline LL div_floor(LL x, LL y) { if(y < 0) x = -x, y = -y; return x < 0 ? (x - y + 1) / y : x / y; }
inline bool calc(LL k, LL b, LL x, LL m, LL target) {
if(k == 0) return (m - x + 1) * b < target;
else if(k > 0) {
LL y = div_ceil(1 - b, k); __int128_t ret = 0;
if(m >= y) ret += (m - std::max(x, y) + 1) * b + (__int128_t)(m + std::max(x, y)) * (m - std::max(x, y) + 1) / 2 * k;
if(x < y) ret += std::min(m + 1, y) - x;
return ret < target;
} else {
LL y = div_floor(1 - b, k); __int128_t ret = 0;
if(x <= y) ret += (std::min(m, y) - x + 1) * b + (__int128_t)(std::min(m, y) + x) * (std::min(m, y) - x + 1) / 2 * k;
if(m > y) ret += m - std::max(x - 1, y);
return ret < target;
}
}
bool check(int m) {
// printf("check %d\n", m);
for(int i = 1; i <= n; i++) {
int l = 1, r = n + 1;
while(l < r) {
int mid = (l + r) >> 1;
if(calc(qk[i], qb[i], mid, m, a[i])) r = mid;
else l = mid + 1;
}
bd[i] = l - 1;
// printf("bd[%d] = %d\n", i, bd[i]);
}
dfs(1, 0);
for(int i = 1; i <= n; i++) if(bd[i] < 1) return false;
// for(int i = 1; i <= n; i++) printf("bd[%d] = %d\n", i, bd[i]);
for(int i = 1; i <= n; i++) cnt[i] = 0;
for(int i = 1; i <= n; i++) cnt[bd[i]]++;
int sum = 0;
for(int i = 1; i <= n; i++) {
sum += cnt[i];
if(sum > i) return false;
}
return true;
}
int main() {
//freopen("tree.in", "r", stdin);
//freopen("tree.out", "w", stdout);
scanf("%d", &n);
for(int i = 1; i <= n; i++) scanf("%lld%lld%lld", &a[i], &qb[i], &qk[i]);
for(int i = 1; i < n; i++) { int u, v; scanf("%d%d", &u, &v); add_edge(u, v), add_edge(v, u); }
// for(int i = 1; i <= n; i++) if(calc(qk[i], qb[i], 1, 1000000000, a[i])) { printf("%lld %lld\n", qk[i], qb[i]); return 0; }
int l = n, r = 1e9;
while(l < r) {
int mid = (l + r) >> 1;
if(check(mid)) r = mid;
else l = mid + 1;
}
printf("%d\n", l);
return 0;
}
95pts #12 TLE(卡常?