0分45行代码求助!!!
查看原帖
0分45行代码求助!!!
1117497
ianwusb楼主2023/10/31 00:13

0分45行代码求助!!! 感谢各位大佬!!!

#include <stdio.h>
int main()
{
    int a[13],b[13];
    int i,sum=0,flag,c;
    for (i=1;i<=12;i++)
    {
        scanf("%d",&a[i]);
        b[i]=0;
    }
    for (i=1;i<=12;i++)
    {
        printf("%d\n",a[i]);
    }
    b[1]=300-a[1];
    printf("b[2]   %d\n",b[1]);
    for (i=1;i<12;i++)
    {
        b[i+1]=b[i]+300-a[i+1];
        printf("a[i+1]  %d\n",a[i+1]);
        printf("b[i+1]  %d\n",b[i+1]);
        if (b[i+1]<0)
        {
            printf("i  -%d\n",(i+1));
            flag=0;
            break;
        }
        if (b[i+1]>=100)
        {
            sum=sum+(b[i+1]/100)*100;
            printf("sum  %d\n",sum);
            b[i+1]=b[i+1]-(b[i+1]/100)*100;
            printf("b[i+1]   %d\n",b[i+1]);
            flag=1;
            c=b[i+1];
            continue;
        }
    }
    if (flag==1)
    {
        printf("sum*1.2+c   %.0f\n",sum*1.2+c);
    }
    
    
}


2023/10/31 00:13
加载中...