#include <cstdio>
#include <cmath>
using namespace std;
int main() {
	int n, k, q = 0;
	scanf("%d%d", &n, &k);
	if (n >= 1) {
		if (n >= 10) {
			if (n >= 100) {
				if (n >= 1000) {
					if (n >= 10000) {
						if (n >= 100000) {
							int a, b, c, d, e, f;
							a = n % 100000 % 10000 % 1000 % 100 % 10;
							b = (n % 100000 % 10000 % 1000 % 100 - a) / 10;
							c = (n % 100000 % 10000 % 1000 - b - a) / 100;
							d = (n % 100000 % 10000 - c - b - a) / 1000;
							e = (n % 100000 - d - c - b - a) / 10000;
							f = (n - e - d - c - b - a) / 100000;
							if (a == 3) {
								q += 1;
							}
							if (b == 3) {
								q += 1;
							}
							if (c == 3) {
								q += 1;
							}
							if (d == 3) {
								q += 1;
							}
							if (e == 3) {
								q += 1;
							}
							if (f == 3) {
								q += 1;
							}
							if (n % 19 == 0 && q == k) {
								printf("YES");
							} else {
								printf("NO");
							}
							return 0;
						}
						int a, b, c, d, e;
						a = n % 10000 % 1000 % 100 % 10;
						b = (n % 10000 % 1000 % 100 - a) / 10;
						c = (n % 10000 % 1000 - b - a) / 100;
						d = (n % 10000 - c - b - a) / 1000;
						e = (n - d - c - b - a) / 10000;
						if (a == 3) {
							q += 1;
						}
						if (b == 3) {
							q += 1;
						}
						if (c == 3) {
							q += 1;
						}
						if (d == 3) {
							q += 1;
						}
						if (e == 3) {
							q += 1;
						}
						if (n % 19 == 0 && q == k) {
							printf("YES");
						} else {
							printf("NO");
						}
						return 0;
					}
					int a, b, c, d;
					a = n % 1000 % 100 % 10;
					b = (n % 1000 % 100 - a) / 10;
					c = (n % 1000 - b - a) / 100;
					d = (n - c - b - a) / 1000;
					if (a == 3) {
						q += 1;
					}
					if (b == 3) {
						q += 1;
					}
					if (c == 3) {
						q += 1;
					}
					if (d == 3) {
						q += 1;
					}
					if (n % 19 == 0 && q == k) {
						printf("YES");
					} else {
						printf("NO");
					}
					return 0;
				}
				int a, b, c;
				a = n % 100 % 10;
				b = (n % 100 - a) / 10;
				c = (n - a - b) / 100;
				if (a == 3) {
					q += 1;
				}
				if (b == 3) {
					q += 1;
				}
				if (c == 3) {
					q += 1;
				}
				if (n % 19 == 0 && q == k) {
					printf("YES");
				} else {
					printf("NO");
				}
				return 0;
			}
			int a, b;
			a = n % 10;
			b = (n - a) / 10;
			if (a == 3) {
				q += 1;
			}
			if (b == 3) {
				q += 1;
			}
			if (n % 19 == 0 && q == k) {
				printf("YES");
			} else {
				printf("NO");
			}
			return 0;
		}
		printf("NO");
		return 0;
	}
	return 0;
}

无语