50分求调
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50分求调
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chienyu楼主2023/10/16 14:46
#include <bits/stdc++.h>
using namespace std;
int n;
int a[105], b[105], sum, s;
int main()
{
	cin >> n;
	for(int i = 1; i <= n; i ++)
	{
		cin >> a[i] >> b[i];
		sum += 100 / a[i] * b[i];
	}
	cin >> s;
	if(sum >= s)
	{
		cout << "Already Au.";
		return 0;
	}
	for(int i = 1; i <= n; i ++)
	{
		if(sum + 100 * (a[i] - b[i]) >= s)
			cout << ceil((s - sum) / 1.0 / (100 / a[i])) << "\n";
		else	cout << "NaN\n";
	}
	return 0;
}
2023/10/16 14:46
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