Rt.Public Noip Round #3 T3 Submission 10'
式子是
dp[n]=∑i≥ni=Ndp[i]−∑i⊕n≥idp[i⊕n]dp[n]=\sum^{i=N}_{i\geq n} dp[i] - \sum_{i\oplus n\geq i}dp[i\oplus n]dp[n]=∑i≥ni=Ndp[i]−∑i⊕n≥idp[i⊕n]
顺便求评价一下此场难度（
