#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 5;
long long a[N], sum[N], n, k, maxi=-1e18;
int main()
{
cin >> n >> k;
for(int i = 1;i <= n-1;i ++)
{
cin >> a[i];
sum[i] = sum[i-1] + a[i];
}
for(int i = 1; i + k-1 <= n-1;i ++)
{
maxi = max (maxi, sum[i + k-1] - sum[i-1]);
}
cout << sum[n-1] - maxi << endl;
return 0;
}
加在哪儿