rt,代码如下:
#include <iostream>
#include <cstring>
using namespace std;
typedef long long LL;
const int N = 100010,M = 2 * N;
int n,m;
int h[N],e[M],ne[M],idx;
int dfn[N],low[N],timestamp;
int cut_cnt;
bool cut[N];
int root;
int vis[N],cnt,num;
void add (int a,int b) {
e[idx] = b;
ne[idx] = h[a];
h[a] = idx++;
}
void tarjan (int u,int fa) {
dfn[u] = low[u] = ++timestamp;
for (int i = h[u];~i;i = ne[i]) {
int j = e[i];
if (j == fa) continue;
if (!dfn[j]) {
tarjan (j,u);
low[u] = min (low[u],low[j]);
if (low[j] >= dfn[u]) {
if (u != root) cut[u] = true;
else cut_cnt++;
}
}
else low[u] = min (low[u],dfn[j]);
}
}
void dfs (int u) {
vis[u] = cnt;
num++;
for (int i = h[u];~i;i = ne[i]) {
int j = e[i];
if (cut[j] && vis[j] != cnt) {
cut_cnt++;
vis[j] = cnt;
}
if (!vis[j]) dfs (j);
}
}
int main () {
int T = 1;
while (cin >> m,m) {
memset (h,-1,sizeof (h));
memset (dfn,0,sizeof (dfn));
memset (low,-1,sizeof (low));
memset (vis,0,sizeof (vis));
memset (cut,false,sizeof (cut));
timestamp = idx = cnt = n = 0;
while (m--) {
int a,b;
cin >> a >> b;
add (a,b),add (b,a);
n = max (n,max (a,b));
}
for (int i = 1;i <= n;i++) {
if (!dfn[i]) {
root = i;
cut_cnt = 0;
tarjan (i,i);
if (cut_cnt >= 2) cut[i] = true;
}
}
LL ans1 = 0,ans2 = 1;
for (int i = 1;i <= n;i++) {
if (!vis[i] && !cut[i]) {
cnt++;
num = cut_cnt = 0;
dfs (i);
if (!cut_cnt) {
if (num > 1) {
ans1 += 2;
ans2 *= (num - 1) * num / 2;
}
else ans1++;
}
else if (cut_cnt == 1) {
ans1++;
ans2 *= num;
}
}
}
cout << "Case " << T++ << ": " << ans1 << ' ' << ans2 << endl;
}
return 0;
}
还有UVA的经验有没有什么输出格式要注意?