#include<bits/stdc++.h>
using namespace std;
int n,a[200005];
double x=0.0;
double y,ans=0;
int main()
{
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a[i];
x=x+(double)a[i];
}
x=x/(double)n;
for(int i=1;i<=n;i++)
{
y=a[i]-x;
if(y<0)
ans-=y;
else
break;
}
cout<<ans;
return 0;
}