#include<bits/stdc++.h>
using namespace std;
#define ll long long
const int N = 5e5 + 10;
int n, h[N], cnt, low[N], dfn[N], tot, point[N], D_p[N], T, S, vis[N];
struct e
{
int n, t;
}lb[N * 2];
void jb(int u, int v)
{
lb[++cnt].n = h[u]; lb[cnt].t = v; h[u] = cnt;
}
bool dfs(int u, int f)
{
vis[u] = 1;
for(int i = h[u]; i; i = lb[i].n)
{
int v = lb[i].t;
if(vis[v]) continue;
vis[v] = 1;
point[v] = 1;
if(v == S) return 1;
if(dfs(v, u)) return 1;
point[v] = 0;
}
return 0;
}
void Dp(int u, int f)
{
low[u] = dfn[u] = ++tot;
int son = 0;
for(int i = h[u]; i; i = lb[i].n)
{
int v = lb[i].t;
if(!dfn[v])
{
Dp(v, u);
son++;
low[u] = min(low[u], low[v]);
if(dfn[u] <= low[v] && f) D_p[u] = 1;
}
else low[u] = min(low[u], dfn[v]);
}
if(f == 0 && son >= 2)
{
D_p[u] = 1;
// cout<<son<<"\n";
}
}
int main()
{
cin >> n;
while(1)
{
int u, v; scanf("%d%d", &u, &v);
if(u == 0 && v == 0) break;
jb(u, v), jb(v, u);
}
cin >> T >> S;
vis[T] = 1;
point[T] = 1;
dfs(T, 0);
// for(int i = 1; i <= n; i++)
// cout<<point[i]<<" ";
// cout<<"\n";
Dp(1, 0);
// for(int i = 1; i <= n; i++)
// cout<<D_p[i]<<" ";
// cout<<"\n";
for(int i = 1; i <= n; i++)
if(D_p[i] && point[i] && i != S && i != T)
{
cout<<i; return 0;
}
cout<<"No solution";
return 0;
}
一个问题:从起点到终点的任意一条路径一定包含答案,对吗qwq