样例过不了求调/kk
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样例过不了求调/kk
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BalanceSegment楼主2023/7/24 11:02
#include <bits/stdc++.h> 
using namespace std;
#define lc id << 1
#define rc id << 1 | 1
const int maxn = 6e4 + 1;
const int inf = 2e9;
int cur, cnt, n, q;
int h[maxn], p[maxn], nxt[maxn];
int w[maxn];
int son[maxn], siz[maxn], dep[maxn], top[maxn], dfn[maxn], fa[maxn], rnk[maxn];
void add_edge(int x, int y) {
	cur++;
	nxt[cur] = h[x];
	h[x] = cur;
	p[cur] = y;
}
struct seg {
	int sum[maxn * 2], maxx[maxn * 2];
	void maintain(int id) {
		sum[id] = sum[lc] + sum[rc];
		maxx[id] = max(maxx[lc], maxx[rc]);
	}
	void build(int id, int l, int r) {
		if(l == r) {
			sum[id] = maxx[id] = w[rnk[l]];
			return;
		}
		int mid = l + r >> 1;
		build(lc, l, mid);
		build(rc, mid + 1, r);
		maintain(id);
	}
	int qrymax(int id, int l, int r, int ql, int qr) {
		if(l > qr || r < ql) return -inf;
		if(ql <= l && qr <= r) return maxx[id];
		int mid = l + r >> 1;
		return max(qrymax(lc, l, mid, ql, qr), 
			qrymax(rc, mid + 1, r, ql, qr));
	}
	int qrysum(int id, int l, int r, int ql, int qr) {
		if(l > qr || r < ql) return 0;
		if(ql <= l && qr <= r) return sum[id];
		int mid = l + r >> 1;
		return qrysum(lc, l, mid, ql, qr) + 
			qrysum(rc, mid + 1, r, ql, qr);
	}
	void update(int id, int l, int r, int x, int t) {
	    if(l == r) {
	      maxx[id] = sum[id] = t;
	      return;
	    }
	    int mid = l + r >> 1;
	    if(x <= mid) update(lc, l, mid, x, t);
	    else update(rc, mid + 1, r, x, t);
	    maintain(id);
	}
} st;
int dfs1(int u, int depth) {
	son[u] = -1;
	siz[son[u]] = 0;
	dep[u] = depth;
	siz[u] = 1;
	for(int j = h[u]; j; j = nxt[j]) {
		int v = p[j];
		if(!dep[v]) {
			siz[u] += dfs1(v, depth + 1);
			fa[v] = u;
			if(son[u] == -1 || siz[v] > siz[son[u]])
				son[u] = v;		
		}
	}
	return siz[u];
}
void dfs2(int u, int tp) {
	top[u] = tp;
	cnt++;
	dfn[u] = cnt;
	rnk[cnt] = u;
	if(son[u] != -1) {
		dfs2(son[u], tp);
		for(int j = h[u]; j; j = nxt[j]) {
			if(p[j] != son[u] && p[j] != fa[u])
				dfs2(p[j], p[j]);
		}
	}
}
int getmax(int x, int y) {
	int ret = -inf;
	int fx = top[x];
	int fy = top[y];
	while(fx != fy) {
		if(dep[fx] >= dep[fy]) {
			ret = max(ret, st.qrymax(1, 1, n, dfn[fx], dfn[x]));
			x = fa[fx];
		}
		else {
			ret = max(ret, st.qrymax(1, 1, n, dfn[fy], dfn[y]));
			y = fa[fy];
		}
		fx = top[x], fy = top[y];
	}
	int mn = min(dfn[x], dfn[y]);
	int mx = max(dfn[x], dfn[y]);
	return max(ret, st.qrymax(1, 1, n, mn, mx));
}
int getsum(int x, int y) {
	int ret = 0;
	int fx = top[x];
	int fy = top[y];
	while(fx != fy) {
		if(dep[fx] >= dep[fy]) {
			ret += st.qrysum(1, 1, n, dfn[fx], dfn[x]);
			x = fa[fx];
		}
		else {
			ret += st.qrysum(1, 1, n, dfn[fy], dfn[y]);
			y = fa[fy];
		}
		fx = top[x], fy = top[y];
	}
	int mn = min(dfn[x], dfn[y]);
	int mx = max(dfn[x], dfn[y]);
	return ret + st.qrysum(1, 1, n, mn, mx);
}
int main() {
	cin >> n;
	for(int i = 1, x, y; i < n; i++) {
		cin >> x >> y;
		add_edge(x, y);
		add_edge(y, x);
	}
	for(int i = 1; i <= n; i++) cin >> w[i];
	dfs1(1, 1);
	dfs2(1, 1);
	st.build(1, 1, n);
	cin >> q;
	char op[10];
	int u, v;
	while(q--) {
		cin >> op >> u >> v;
		if(!strcmp(op, "CHANGE"))
			st.update(1, 1, n, dfn[u], v);
		else if(!strcmp(op, "CHANGE"))
			cout << getmax(u, v) << endl;
		else cout << getsum(u, v) << endl;
	}
	return 0;
}
2023/7/24 11:02
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