#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int maxn = 2e5 + 5;
int n, m, t;
struct SegmentTree {
int left, right;
int minv, tag;
SegmentTree() : left(0), right(0), minv(0), tag(0) { }
} tree[maxn << 2];
inline void pushup(int root) {
tree[root].minv = min(tree[root << 1].minv, tree[root << 1 | 1].minv);
}
inline void pushdown(int root) {
if (!tree[root].tag) return;
tree[root << 1].minv += tree[root].tag;
tree[root << 1 | 1].minv += tree[root].tag;
tree[root << 1].tag += tree[root].tag;
tree[root << 1 | 1].tag += tree[root].tag;
tree[root].tag = 0;
}
void build(int root, int l, int r) {
tree[root].left = l;
tree[root].right = r;
if (l == r) {
tree[root].minv = 0;
tree[root].tag = 0;
return;
}
int mid = (l + r) >> 1;
build(root << 1, l, mid);
build(root << 1 | 1, mid + 1, r);
pushup(root);
}
// 单点修改
void solUpdate(int root, int pos) {
if (tree[root].left == tree[root].right) {
tree[root].minv++;
tree[root].tag++; // 没有这一行就会错
return;
}
pushdown(root);
int mid = (tree[root].left + tree[root].right) >> 1;
if (mid >= pos) solUpdate(root << 1, pos);
else solUpdate(root << 1 | 1, pos);
pushup(root);
}
// 区间修改
void mulUpdate(int root, int l, int r) {
if (tree[root].left >= l && tree[root].right <= r) {
tree[root].minv++;
tree[root].tag++;
return;
}
pushdown(root);
int mid = (tree[root].left + tree[root].right) >> 1;
if (mid >= l) mulUpdate(root << 1, l, r);
if (mid < r) mulUpdate(root << 1 | 1, l, r);
pushup(root);
}
int main() {
scanf("%d", &t);
while (t--) {
bool edited = false;
int ans;
scanf("%d%d", &n, &m);
fill(tree, tree + (n << 2), SegmentTree());
build(1, 1, n);
for (int i = 1; i <= m; i++) {
int action, pos;
scanf("%d%d", &action, &pos);
if (edited) continue;
if (action == 1) {
solUpdate(1, pos);
} else if (action == 2) {
mulUpdate(1, 1, pos - 1);
mulUpdate(1, pos + 1, n);
}
if (tree[1].minv > 0) {
ans = i;
edited = true;
}
}
if (edited) printf("%d\n", ans);
else printf("-1\n");
}
return 0;
}
代码如上,如果把注释标注出来的那一行删去就会错。 但是这是单点修改,把叶子节点打上懒标记又不会下传,为什么会错呢?