数学题求助
1、 已知数列{an},{bn}\{a_n\},\{b_n\}{an},{bn}均为等差数列,其前 nnn 项和分别为 Sn,TnS_n,T_nSn,Tn,若 SnTn=4n+23n−1\dfrac{S_n}{T_n}=\dfrac{4n+2}{3n-1}TnSn=3n−14n+2,则 a9b9=\dfrac{a_9}{b_9}=b9a9=( ),a9b8=\dfrac{a_9}{b_8}=b8a9=( )
2、 求证: 11+2+222+2+⋯+n2n+n<2(n∈N∗\frac{1}{1+2}+\frac{2}{2^2+2}+\cdots+\frac{n}{2^n+n}<2\quad(n\in \mathbb{N^*}1+21+22+22+⋯+2n+nn<2(n∈N∗ 3、 设 Sn=1×2+2×3+⋯+n(n+1)S_n=\sqrt{1\times2}+\sqrt{2\times 3}+\cdots+\sqrt{n(n+1)}Sn=1×2+2×3+⋯+n(n+1),求证:n(n+1)2<Sn<n(n+2)2(n∈N∗)\dfrac{n(n+1)}{2}<S_n<\dfrac{n(n+2)}{2}\quad(n\in \mathbb{N^*)}2n(n+1)<Sn<2n(n+2)(n∈N∗)