我的代码用的是暴力枚举

#include<iostream>
using namespace std;

int a[100001];
int b[100001];
char g[1001][1001]; 
int main(){
	
	
	int ans = 0;
	int n;
	cin >> n;
	for(int i = 0; i < n; i++){
		for(int j = 0; j < n; j++){
			cin >> g[i][j];
		}
	}
	int hh = 0;
	for(int i = 0; i < n; i++){
		for(int j = 0; j < n; j++){
			if(g[i][j] == 'y' and g[i][j + 1] == 'i' and g[i][j + 2] == 'z' and g[i][j + 3] == 'h' and g[i][j + 4] == 'o' and g[i][j + 5] == 'n' and g[i][j + 6] == 'g') ans++;
			if(g[i][j] == 'y' and g[i][j - 1] == 'i' and g[i][j - 2] == 'z' and g[i][j - 3] == 'h' and g[i][j - 4] == 'o' and g[i][j - 5] == 'n' and g[i][j - 6] == 'g') ans++;
			if(g[i][j] == 'y' and g[i + 1][j] == 'i' and g[i + 2][j] == 'z' and g[i + 3][j] == 'h' and g[i + 4][j] == 'o' and g[i + 5][j] == 'n' and g[i + 6][j] == 'g') ans++;
			if(g[i][j] == 'y' and g[i - 1][j] == 'i' and g[i - 2][j] == 'z' and g[i - 3][j] == 'h' and g[i - 4][j] == 'o' and g[i - 5][j] == 'n' and g[i - 6][j] == 'g') ans++;
			if(g[i][j] == 'y' and g[i + 1][j + 1] == 'i' and g[i + 2][j + 2] == 'z' and g[i + 3][j + 3] == 'h' and g[i + 4][j + 4] == 'o' and g[i + 5][j + 5] == 'n' and g[i + 6][j + 6] == 'g') ans++;
			if(g[i + 1][j] == 'y' and g[i + 2][j + 1] == 'i' and g[i + 3][j + 2] == 'z' and g[i + 4][j + 3] == 'h' and g[i + 5][j + 4] == 'o' and g[i + 6][j + 5] == 'n' and g[i + 7][j + 6] == 'g') ans++;
			else{
				hh = 1;
			}
 		}
	}
	if(hh == 1){
		for(int i = 0; i < n; i++){
			for(int j = 0; j < n; j++){
				g[i][j] = '*';
			}
		}
	}
	for(int i = 0; i < n; i++){
		for(int j = 0; j < n; j++){
			cout << g[i][j];
		}
		cout << endl;
	}
	return 0;
}