测评详情

#include <iostream>
#include <iomanip>
using namespace std;
int main() {
	int n, k, a1[5005], a2[5005], cnt1 = 0, cnt2 = 0, sum1 = 0, sum2 = 0;
	cin >> n >> k;
	for (int i = 1; i <= n; i++) {
		if (i % k == 0) a1[++cnt1] = i;
		else a2[++cnt2] = i;
	}
	for (int i = 1; i <= cnt1; i++) sum1 += a1[i];
	for (int i = 1; i <= cnt2; i++) sum2 += a2[i];
	cout << fixed << setprecision(1) << 1.0 * sum1 / cnt1 << " " << 1.0 * sum2 / cnt2;
	return 0;
}