这道题是5506，是个模拟题，A操作先没有写，错的和M操作一样，就是68行注释掉的地方，题目说数据不超过100，我就想着循环200次，后来试了试不管数据是多少，第15个点都过不去，不知道逻辑上哪里出错了，换成while就过了，有没有老哥帮忙看看，xyz的范围也没有限制，就算for循环出现坐标绝对值超过100，但是后面还有判断，应该不会影响啊，

#include <bits/stdc++.h>

#define fi first
#define se second
#define pb push_back
#define mk make_pair
#define sz(x) ((int) (x).size())
#define all(x) (x).begin(), (x).end()

using namespace std;

typedef long long ll;
typedef vector<int> vi;
typedef pair<int, int> pa;

const int N = 105;

int dx[5][8] = {0, 0, 0, 0, 0, 0, 0, 0,
                1, 1, 0, -1, -1, -1, 0, 1,
                1, 1, 0, -1, -1, -1, 0, 1,
                1, 1, 0, -1, -1, -1, 0, 1,
                0, 0, 0, 0, 0, 0, 0, 0};
int dy[5][8] = {0, 0, 0, 0, 0, 0, 0, 0,
                0, 1, 1, 1, 0, -1, -1, -1,
                0, 1, 1, 1, 0, -1, -1, -1,
                0, 1, 1, 1, 0, -1, -1, -1,
                0, 0, 0, 0, 0, 0, 0, 0};
int dz[5][8] = {-1, -1, -1, -1, -1, -1, -1, -1,
                -1, -1, -1, -1, -1, -1, -1, -1,
                0, 0, 0, 0, 0, 0, 0, 0,
                1, 1, 1, 1, 1, 1, 1, 1,
                1, 1, 1, 1, 1, 1, 1, 1};

int main() {
    int n, t;
    cin >> n >> t;
    int x[N], y[N], z[N], h[N], f[N], atk[N], def[N], mat[N], mdf[N], hp[N], fix[N];
    string op[N];
    for (int i = 0; i < n; i++) {
        cin >> x[i] >> y[i] >> z[i] >> h[i] >> f[i] >> atk[i] >> def[i] >> mat[i] >> mdf[i] >> hp[i] >> fix[i] >> op[i];
    }
    for (int j = 0; j < t; j++) {
        for (int i = 0; i < n; i++) {
            if (hp[i] <= 0) continue;
            x[i] += dx[h[i]][f[i]];
            y[i] += dy[h[i]][f[i]];
            z[i] += dz[h[i]][f[i]];
        }
        for (int i = 0; i < n; i++) {
            if (hp[i] <= 0) continue;
            if (op[i][j] == 'N') continue;
            else if (op[i][j] == 'U') {
                if (h[i] < 4) h[i]++;
            } else if (op[i][j] == 'D') {
                if (h[i] > 0) h[i]--;
            } else if (op[i][j] == 'L') {
                if (f[i] < 7) f[i]++;
                else f[i] = 0;
            } else if (op[i][j] == 'R') {
                if (f[i]) f[i]--;
                else f[i] = 7;
            } else if (op[i][j] == 'F') {
                hp[i] += fix[i];
            } else if (op[i][j] == 'A') {
                ;
            } else {
                int xx = x[i], yy = y[i], zz = z[i], hh = h[i], ff = f[i];
                //for (int k = 0; k < 200; k++) {
                while (abs(xx) < 200 && abs(yy) < 200 && abs(zz) < 200) {
                    xx += dx[hh][ff];
                    yy += dy[hh][ff];
                    zz += dz[hh][ff];
                    for (int kk = 0; kk < n; kk++) {
                        if (xx == x[kk] && yy == y[kk] && zz == z[kk]) {
                            if (mat[i] > mdf[kk]) hp[kk] -= mat[i] - mdf[kk];
                        }
                    }
                }
            }
        }
    }
    for (int i = 0; i < n; i++) cout << x[i] << " " << y[i] << " " << z[i] << " " << max(0, hp[i]) << endl;
    return 0;
}