#include <iostream>
using namespace std;
int n, p, ans = -1, a[5000005];
int main() {
cin >> n >> p;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
for (int i = 1; i <= p; i++) {
int x, y, z;
cin >> x >> y >> z;
for (int j = x; j <= y; j++) {
a[j] += z;
}
}
for (int i = 1; i <= n; i++) {
if (a[i] > ans) {
ans = a[i];
}
}
cout << ans;
return 0;
}
显示超时